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7n^2+77n+210=0
a = 7; b = 77; c = +210;
Δ = b2-4ac
Δ = 772-4·7·210
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(77)-7}{2*7}=\frac{-84}{14} =-6 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(77)+7}{2*7}=\frac{-70}{14} =-5 $
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